Question

4. Calculate the size of each lettered angle in the following figures :​

Answer 1

Answer:

Hence,x=32°, y=64°, z=52°

Step-by-step explanation:

In ∆ABC,

AC=BC, Given

✓ABC=√BAC (✓s opposite to equal sides)

√ABC=32°

=x=32°

Now, y= 32°+32°=64°

• ( Exterior angle= Sum of two opposite interior √s)

In∆BCD,

BC=BD

√BDC=√BCD(√s opposite√c equal sides)

√BDC= y=√BCD

√BDC= 64°=√BCD

Now, z+64°+64°=180° ( Sum of √s of a ∆ )

=z+128° =180°

=z =180°-128° =52°

Answer

Hence, x=32°, y=64°, z=52°