4. Calculate the weight and the percentage of zinc in
the zinc-copper alloy being given that the latter's
alloy with 3 kg of pure zinc contains 90 per cent of
zinc and with 2 kg of 90% zinc alloy contains 84%
of zinc.
Answers
Given:
First quantity = 3kg
Percentage of Zinc = 90%
Second quantity = 2kg
Percentage of Zinc = 90%
Percentage of alloy = 84%
To Find:
Weight and the percentage of zinc in the zinc-copper alloy
Solution:
Let x : 3 , then y : 90%
Thus, 10 : 90 – y
(90-y)/3 = 10/x --- eq 1
In second case,
Let x : 2 , then y : 90%
Therefore (84-y)/2 = 6/x --- eq 2
Dividing (1) and (2)
= 180 – 2y = 420 – 5y
3y = 240
y = 80
x = 30/(90-80)
= 30/10
= 3 kg
Quantity of zinc in x = 80% of x
= 0.8 × 3
= 2.4 kg
Answer: Weight and percentage of zinc is 2.4 kg or 80%
- The weight and the percentage of zinc in the zinc - copper alloy is equal to 2.4 kg and 80% .
Given :-
- Alloy with 3 kg of pure zinc contains 90 per cent of zinc .
- Also, alloy with 2 kg of 90% zinc alloy contains 84% of zinc .
Solution :-
Let initially allow has zinc and copper in the ratio z : c .
when 3 kg of pure zinc is added
→ (z + 3) : c = 9 : 1
→ z + 3 = 9c
→ 9c - z = 3 ------ Eqn.(1)
also, when 2kg of alloy with 90% zinc is added :-
→ zinc added = 2 * 0.9= 1.8 kg
→ copper added = 2 - 1.8 = 0.2 kg .
Now it is given that, we gets 84% of zinc .
So,
→ (z + 1.8)/(z + c + 2) = 84/100 = 21/25
→ 25z + 45 = 21c + 21z + 42
→ 21c - 4z = 3 ------- Eqn. (2)
Multiplying Eqn.(1) by 4 and subtracting Eqn.(2) from result :-
→ 4(9c - z) - (21c - 4z) = 4*3 - 3
→ 36c - 21c + 4z - 4z = 12 - 3
→ 15c = 9
→ c = 3/5
putting c in Eqn.(1) :-
→ 9(3/5) - z = 3
→ z = (27/5) - 3
→ z = (27 - 15)/5
→ z = (12/5)
→ z = 2.4 kg (Ans.)
therefore,
→ Required % = (12/5) * 100 * (1/3) = 80% (Ans.)
Hence, the weight of zinc in zinc - copper alloy is equal to 2.4 kg and the percentage of zinc in the zinc - copper alloy is equal to 80% .
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