Question

4. Certain force acting on a 20 kg mass changes its velocity from 5 ms' to 2 m/s. Calculate the work done by the force.
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Answer 1

Explanation:

Initial velocity    u=5  m/s

Final velocity     v=2  m/s

The work done is equal to the change in the kinetic energy of an object.

W=(1/2)m(v²−u²)

W=(1×20÷2)×(2²−5²) J

W=10 × (4 - 25) J

W= 10 × -21 J

W = -210 J

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