Question

4 chairs and 3 tables cost rupees 2100 and 5 chairs and 2 tables cost rupees 1750 find the cost of one chair and one table separately​

Answer 1

Step-by-step explanation:

Let the price of a table and chair be x ruppees and y ruppees. Then

4x+3y=2100...(1)×2 and

5x+2y=1750...(2)×3

Subtract (1) from (2) we get

15x+6y-(8x+6y)=5250-4200=>7x=1050 =>x=150. So substitute x=>150 in (1) =>

4(150)+3y=2100 =>3y=2100-600=1500 =>y=500. So the cost of one chair and one table separately are 500 and 150 ruppees respectively. Hope it helps you.

Answer 2

This answer is by Acrel

Answer:

Cost of one chair is Rupees 150

Cost of one table is Rupees 500.

Step-by-step explanation:

Assuming:

Let the cost of one chair be x rupees.

Let the cost of one table be y rupees.

According To Question:

4x + 3y = 2100 -----------Equation 1

5x + 2y = 1750 ------------Equation 2

Solving these Equations by Elimination method:

Multiplying Equation 1 by 2 and Equation 2 by 3:

8x + 6y = 4200 -----------------Equation 3

15x + 6y = 5250 ----------------Equation 4

Subtracting Equation 3 from  Equation 4:

15x + 6y = 5250

8x + 6y = 4200

7x = 1050

x = 1050 / 7 = 150

Putting x = 150 in Equation 1:

4 * 150 + 3y = 2100

3y = 2100 - 600

3y = 1500

y = 1500 / 3

y = 500

Therefore, cost of 1 chair is Rupees 150 and cost of one table is Rupees 500.