Question

4 chairs and 3tables cost Rs2100 and 5 chairs qnd 2 tables cost Rs1750. Find the cost of one chair and one table seperately

Answer 1

Hey friend..!! here your answer
________________________

let the chair equal to x
table equal to y

according to question

4 x + 3 Y = 2100 ------1
5 x + 2 Y = 1750 -------2

by solving elimination method equation 1 and 2

4 x + 3 Y = 2100 × 5
5 x + 2 Y = 1750 x 4

20 X + 15 Y = 10500
20 X + 8 y = 7000
______________
7y = 3500

we get ,
y = 500

put the value of Y in equation 1

4x + 3(500) = 2100
4x + 1500 = 2100
4x = 600
x = 150

so that the cost of chair is 150 rupees and cost of table is 500.

Hope it helps you!

Answer 2

Given data : 4 chairs and 3 tables cost Rs 2100 and 5 chairs and 2 tables cost Rs 1750.

Solution : Let, the cost of one chair be x and the cost of one table be y.

Now, according to the given data;

• 4x + 3y = 2100 ----{1}

• 5x + 2y = 1750 ----{2}

Now, multiply eq. {1} by 2

• 8x + 6y = 4200 ----{3} and similarly,

Multiply eq. {2} by 3

• 15x + 6y = 5250 ----{4}

Now, subtract eq. {3} from eq. {4}

15x + 6y = 5250

- (8 + 6y) = 4200

______________

7x = 1050

x = 1050/7

x = 150

Now, put value of x in eq. {1}

➜ 4x + 3y = 2100

➜ 4*(150) + 3y = 2100

➜ 600 + 3y = 2100

➜ 3y = 2100 - 600

➜ 3y = 1500

➜ y = 1500/3

➜ y = 500

Answer : Hence, the cost of one chair is Rs 150 and the cost of one table is Rs 500.

[Verification : Put vale of x and y in eq. {1}

➜ 4x + 3y = 2100

➜ 4*(150) + 3*(500) = 2100

➜ 600 + 1500 = 2100

➜ 2100 = 2100

Hence, it's verified]