Question

4. CHALLENGERS 1. The H.C.Fof two numbers is 23 and their L.C.M is 1449. If one of them is 161, find the other. Mo their CM​

Answer 1

Answer:

Given, HCF=23

LCM=1449

Let the two numbers be a and b. Let a=161. We have to find b.

We know that

HCF(a,b)×LCM(a,b)=a×b

⇒23×1449=161×b

⇒23×

161

1449

=b

⇒b=23×9

∴b=207

Thus, the other number is 207.

Answer 2

Answer:

The other number is 207

Step-by-step explanation:

Let the other number be b,

H.C.F. = 23

L.C.M. = 1449

We know that,

HCF (a, b) × LCM (a, b) = a × b.

23 × 1449 = 161 × b

Or, b = 23 × 1449 / 161

Or, b = 23 × 9

.*. b = 207

.*. The other number is 207

Hope it helps,,,