Question

4. Circles are concentric with centre 0. Find AC if OM = 8 cm, OC = 10 cm
and OB = 17 cm.
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Answer 1

Answer:

Given OA=10cm

OC=6cm

∠OCA= 90

∘

By Pythagoras theorem,

AC

2

=OA

2

−OC

2

=10

2

−6

2

AC=8cm

We know that perpendicular from centre of circle bisects the chord

Therefore AB=2AC

AB=16cm

option D is the answer.