4 cm. Find the area of shaded region.
Semicircles are drawn on AB, AC and BC as
diameters. It is given that AB = 3 cm and AC =
o
DB
So the fig., ABC is a right-angled triangle at A.
Answers
Answered by
1
Answer:
ANSWER
In △ABC,∠A=90
o
By Pythagoras theorem,
BC
2
=AB
2
+AC
2
3
2
+4
2
9+16=25
∴BC=5cm
A(shadded region)=A(△ ABC)+A (semicircle AB) + (semicircle AC) - A(semicircle BAC)
=
2
1
×3×4+
2
1
×π(
2
3
)
2
+
2
1
×π(
2
4
)
2
−
2
1
×π(
2
5
)
2
=6+
8
6π
+2π−
8
25π
=6+2π−2π
=6cm
2
Answered by
1
Answer:
yess upper wale right answer
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