Question

4) Consider the two lines P:= 3x – 4y + 5 = 0 and Q := 4x + 5y – 45 = 0. There 1 point
is another line R := Q + P = 0 passing through the intersection of these two lines. Value
of the constant is ten times the length of the perpendicular distance of the line P from the
origin (0,0). The exact equation of the line R is given by:
ADDITIONAL INFO: In general, the equation of a line passing through the intersection of two
lines P := 2px + bpy + cp = 0 and Q := aqx + bay + cq = 0 is Q + AP= 0, where the
constant is real and can be determined based on additional conditions.
7x – 8y + 5 = 0
34x - 35y + 5 = 0
19x - 20y - 20 = 0
50+6g – 55 = 0​

Answer 1

Answer:

I havent the foggiest idea

Step-by-step explanation:

first dont blow your brain,

second just screw school.

Answer 2

Answer:

The answer is 'B'. 34x-35y+5=0

Step-by-step explanation:

Value of constant is 1

So, R=Q+10P