Question

4. Construct a A ABC in which AB = 5 cm, AC = 4.5 cm and BC = 6 cm.
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Answer 1

Answer:

Steps of construction:

Draw a line segment BC =5 cm.

Taking B & C as draw two arcs of radii 4 cm and 6 cm to intersect each other at A.

Join BA and CA. ...

Now from B draw any ray BX making an acute ∠CBX with base BC on the side opposite to the vertex A.

Along BX Mark 3 points B1,B2,B3, on BX such that BB1 = B1B2 = B2B3 .

Step-by-step explanation:

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Answer 2

Answer:

Steps of construction

1. Draw a line segment XY.

2. Take a point M on XY.

3. Draw ZM⊥XY, with MZ sufficiently large.

4. With M as center and radius 3.6cm, draw an arc, cutting MZ at A.

5. With A as center and radii 4.5cm and 5cm, draw arcs cutting XY at B and C respectively; join AB and AC.

Then ABC is the required triangle.

solution