Question

4 Construct a AABC, in which AB = 6 cm, ZB =60° and ZA = 45°. Construct a APQR similar to AABC such that each side of APQR is 1.5 times that of the corresponding sides of AABC.​

Answer 1

Answer:

I take base BC = 5.5 cm. so A formed will be

A'BC'. SOLUTION:

Given, a right angled A ABC, in which BC

=5.5 cm, AB= 6.5 cm, ZB = 60°

STEPS OF CONSTRUCTION:

1. Draw a line segment BC = 5.5 cm. 2. At B draw LB = 60° and cut off BA = 6.5 cm from it.

3. Join AC. Thus AABC is a given right angled Triangle.

4. Now from B draw a ray BX making an

acute ZCBX on the side opposite to the vertex A.

5. Mark 3 points B1,B2,B3, on BY such that

BB1 B1B2 = B2B3. 6.Join B2C and from B3 draw B3C' || B2C intersecting BC at C.

7. From point C' draw C'A' II CA intersecting AB at A'. Thus, AA'BC' is the required triangle whose sides are 3/2 of the corresponding sides of AABC.

HOPE THIS WILL HELP YOU....

Answer 2

$\huge \: \purple{hi \: army}$

Steps of Construction:

i) Draw a line segment that is sufficiently long using a ruler.

(ii) Locate points A and B on it such that AB=6.5cm.

(iii) Construct a line segment AD, sufficiently large, such that ∠A=45˚

Construct a line segment BE, sufficiently large, such that ∠B=60˚ use a protractor to measure

+iv) Extend AD and BE to intersect at C.

⇒ ABC is the required triangle