4. Construct a triangle ABC, in which :
(1) BC = 4.8 cm, B = 45° and AB - AC = 2.4 cm
(ii) BC = 4.8 cm, B = 45° and AC - AB = 2.4 cm
(iii) AB = 5.3 cm, A = 60° and AC - BC = 2 cm
(iv) AB = 5.3 cm, A = 60° and BC - AC = 2 cm
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1.Draw base BC of length 8cm
2.Now, let's draw ∠B=45
∘
.Let the ray be BX
3.Open the compass to length AB−AC=3.5cm.
Since AB−AC=3.5cm is positive.
So, BD will be above line BC
From point B as center, cut an arc on ray BX.
Let the arc intersect BX at D
4.Join CD
5.Now, we will draw perpendicular bisector of CD
6.Mark point A where perpendicular bisector intersects BD
7.Join AC
Result:∴△ABC is the required triangle.
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