4 ( COS2 60 + SIN2 30 ) - 3( COS2 45 - TAN2 45 ) = 7/2
Answers
Answered by
3
4(cos²60°+sin²30°)-3(cos²45°-tan²45°)
=4[(1/2)²+(1/2)²]-3[(1/√2)²-(1)²]
=4(1/4+1/4)-3(1/2-1)
={4(1+1)/4}-{3(1-2)/2}
=2-(-3/2)
=2+3/2
=(4+3)/2
=7/2
=4[(1/2)²+(1/2)²]-3[(1/√2)²-(1)²]
=4(1/4+1/4)-3(1/2-1)
={4(1+1)/4}-{3(1-2)/2}
=2-(-3/2)
=2+3/2
=(4+3)/2
=7/2
Similar questions