Math, asked by venkat9788, 8 months ago

4 cos36^0 +cot 7 1/2^0 = root theta base 1 + root theta base 2+ root theta base 3 + root theta base 4 + root theta base 5 + root theta base 6( theta base 1 < theta base 2 < theta base 3 < theta base 4 < theta base 5 < theta base 6) then theta base 1 + theta base6/ theta base2 + theta base 5 + theta base 3+ theta base 4/7 -

Answers

Answered by prutha39
0

Answer:

dont know bhai sorry but u can try

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