4. cosec2A-cot-2A find
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It is given that 4cotA=3
Thus cotA=
4
3
=
P
B
P=4, B=3
Now, H
2
=P
2
+B
2
H
2
=3
2
+4
2
H
2
=5
2
H=5
cosec
2
A−cot
2
A=(
P
H
)
2
−(
P
B
)
2
= (
4
5
)
2
−(
4
3
)
2
=
16
25
−
16
9
=
16
16
= 1
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