Math, asked by ovrsmart2378, 5 months ago

4/cot^2 30°+1/sin^2 60°_cos^2 45°_tan^2 45°

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Answered by rajeevr06
2

Answer:

 \frac{4}{( \sqrt{3} ) {}^{2} }  +  \frac{1}{( \frac{ \sqrt{3} }{2}) {}^{2}  }  - ( \frac{1}{ \sqrt{2} } ) {}^{2}  - 1 =

 \frac{4}{3}  +  \frac{4}{3}  -  \frac{1}{2}  - 1 =  \frac{8 + 8 - 3 - 6}{6}  =  \frac{7}{6}

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