Question

4. cot A+ tan (180° + A) + tan (90° + A) + tan (360° – A)= 0.
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Answer 1

Answer:

0

Step-by-step explanation:

CotA + tan(180+A) + tan(90+A)+tan(360-A)

CotA + tan(180+A) + tan(90+A)+tan(360-A)= CotA + tan(2*90+A) + tan(90+A) + tan(4*90-A)

CotA + tan(180+A) + tan(90+A)+tan(360-A)= CotA + tan(2*90+A) + tan(90+A) + tan(4*90-A)= CotA + tanA - CotA - tanA

CotA + tan(180+A) + tan(90+A)+tan(360-A)= CotA + tan(2*90+A) + tan(90+A) + tan(4*90-A)= CotA + tanA - CotA - tanA= 0 = R.H.S proved

Done

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