Question

4 cot square 60°+sec square 30°-2 sin square 45°/sin square 60°+ cos square 45°

Answer 1

Answer:

answer is 4/3

Step-by-step explanation:

(4 cot^2 60° + sec^2 30° - 2 sin^2 45°)/( sin ^2 60° + cos^2 45° )

we know that ,

$\cot(60 ) = 1 \div \sqrt{3}$

$\sec(30) = 2 \div \sqrt{3}$

$\sin(45) = 1 \div \sqrt{2}$

$\sin(60) = \sqrt{3 } \div 2$

$\cos(45) = 1 \div \sqrt{2}$

substituting the above values in our equation ,

we get ,

= [ 4(1/root 3 )^2 + (2/ root 3)^2 - 2 (1/ root 2)^2 ] / [ (root 3 /2 )^2 + (1/ root 2)^2 ]

solving this further , we get ,

(5/3) / (5/4)

5/3 × 4/5 = 4/3

so answer is 4/3.

hope this helps

thnx

Answer 2

Answer:

attached image is answer

Step-by-step explanation:

attached image is answer