Math, asked by abhishekkr10, 4 days ago

4/cot²30° + 1/sin²30° - 2cos²45° - sin²0° ​

Answers

Answered by anishrajarm1
0

Answer:

4/cot230° + 1/sin230° – 2cos245° - sin20° = 4/3 + 4/1 – 1 – 0 = 26/6 = 13/3-4-cot-2-30-1-sin-2-30-2cos-2-45-sin-2-0

Answered by s145810apriya9200
1

Answer:

cot230= (root 3)2= 3

sin230 = (1/2)2=1/4

2 cos245 = 2(1/root 2)2= 2(1/2)= 1

sin20=0

4/3 +1/(1/4) - 1 - 0

= 4/3 +4 -1

= 4/3 +3

= 13/3 = answer

Similar questions