Question

4) DE || QR and AP and BP are bisectors of LEAB and ZRBA,
respectively. Find ZAPB.
D
E
O
B
R​

Answer 1

Answer:

Step-by-step explanation:

Given: DE∥QR, AP bisects ∠EAB, BP bisects ∠RBA

Since, DE∥QR

∠EAB+∠RBA=180  

0

 

2

1

​  

(∠EAB+∠RBA)=90  

0

 

∠PAB+∠PBA=90  

0

 (AP bisects ∠EAB, BP bisects ∠RBA)

Now, In △PAB

∠PAB+∠PBA+∠APB=180  

0

 

90  

0

+∠APB=180  

0

 

∠APB=90  

∘