Question

4. Determine the horizontal force P required to start moving the 500 N block as shown in
figure 4 up the inclined surface. Assume us= 0.3.​

Answer 1

Answer:

P = mg sin 30 + u mgcos 30

= 500 × 1/2 + 0.3 × 500 × √3/2

=509.8 N

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