Question

4
Diagonal AC and BD of a traperium ABCD
with AB//CD intersect each other at o.
Prove that ar (AOD) = ar (BOC)​

Answer 1

Let CD be the base.
Now,
Triangles ACD and BDC lie on the common base CD and lie between parallel lines AB and CD .
Therefore,
Area of triangle BOC is equal to area of triangle AOD .
Now,
subtracting common region COD,
we get area of triangle AOD is equal to area of triangle BOC ,
HENCE PROVED.
Hope you understood

Answer 2

Step-by-step explanation:

PLEASE REFER TO ATTACHMENT

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