Question

4) Diagonal of a parallelogram divide it into two

a) Squares b) Congruent triangle c) Rectangle d) Circlesl​

Answer 1

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Statement : A diagonal of a parallelogram divides it into two congruent triangles.

Given : A parallelogram ABCD.

To prove : ΔBAC ≅ ΔDCA

Construction : Draw a diagonal AC.

Proof :

In ΔBAC and ΔDCA,

∠1 = ∠2 [alternate interior angles]

∠3 = ∠4 [alternate interior angles]

AC = AC [common]

ΔBAC ≅ ΔDCA [ASA]

Hence, it is proved.

Answer 2

b) Congruent triangle