Question

4 dice rolled probability of not getting same number on 3 dices?

Answer 1

Probeblity of same no.on all dices =6

Total chance =1296

=6/1296=216

Answer 2

Solution:

When four Dices are rolled total possible outcome=$6^{4}$=1296

→Probability of not getting same number on 3 dices= 1 - Probability of Same number on three dices.

→Same number on three dices =(1,1,1,2),(1,1,1,3),(1,1,1,4),(1,1,1,5),(1,1,1,6),(1,1,6,1),.........(6,6,6,1).......    = 20×6=120

As Probability of an event=$\frac{\text{Total favorable outcome}}{\text{Total possible outcome} }$

Probability of not getting same number on 3 dices= 1 - $\frac{120}{1296}$ = $\frac{1296-120}{1296}= \frac{1176}{1296}=\frac{147}{162}$