4. Dinitrogen and dihydrogen react with each other to produce ammonia according to the following
chemical equation:
N, () + 3H, (g) -> 2NH3 (8)
(i) Calculate the mass of ammonia produced if 2.00 10° 3 dinitrogen reacts with
1.00 × 10° 3g dihydrogen
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Answers
Answered by
3
Answer:
Explanation:
28 g of N2 reacts with 6g of H2.
1g of N2 reacts with 6/28 g of H2
2000g of N2 will react with 2000× 6/28 = 428.57 of H2
but H2 is given 1 × 10³g > 428.57 g
e.g., H2 is excess available.
hence, N2 is the limiting reagent. it means N2 limits the production of an amount of anomia.
28g of N2 produces 34 g of NH3
1g of N2 produces 34/28 g of NH3
2000g of N2 will produce 34/28 × 2000 = 2428.57 g of NH3.
Answered by
1
Answer:
28.0 g of N2 require 6.0 g of H2 to produce
= 34.0 g of NH3
2.00×103g of N2 will produce
= 28/34 × 2.00 × 10³g of NH3
= 2.43 × 10³g of NH3
= 2430g NH3
Explanation:
hope it will help you...
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