Question

⁴ discus the shape of the following molecules using the VSEPR model : SF4 , H2O​

Answer 1

Shape of H2O is bent as oxygen has two lone pair which repel the bond pairs and angle comes out to be 105. In SF4 Sulfur tetrafluoride has 5 regions of electron density around the central sulfur atom (4 bonds and one lone pair). These are arranged in a trigonal bipyramidal shape with 102° F-S-F bond angles between the equatorial fluorine atoms and 173° between the axial fluorine atoms.

The lone pair takes an equatorial position because it demands more space than the bonds. The result is a disphenoidal or ‘see-saw’ shaped molecule.