Question

4. Divide 24,000 into two parts such that the simple interest on the first part for 4 years at 12% per annum is equal to the simple interest on the second part for 6 years at 16% per annum.​

Answer 1

Answer:

1.5660

2.11520

Step-by-step explanation:

1

p=12000

n=4

r=12

• 12000×4×12/100
• 5660

2

p=12000

n=6

r=16

• 12000×6×16/100
• 11520

Answer 2

Answer:

The parts are 16000 and 8000

Step-by-step explanation:

Given,

Total amount = 24,000

Let first part = x ⇒ Second part = 24000 - x

∵ Annual rate of simple interest in first part = 12%,

Time = 4 years,

Also, simple interest formula,

$I=\frac{P\times r\times t}{100}$

Where,

P = principal, r = rate per period, t = number of periods,

So, the simple interest in first part,

$I_1=\frac{x\times 12\times 4}{100}$

$=\frac{48x}{100}$

Similarly,

Annual rate of simple interest in second part = 16%,

Time = 6 years,

So, the simple interest in second part,

$I_2=\frac{96(24000-x)}{100}$

According to the question,

$I_1=I_2$

$\implies \frac{48x}{100}=\frac{96(24000-x)}{100}$

$48x = 96(24000 - x)$

$48x = 2304000 - 96x$

$48x + 96x = 2304000$

$144x = 2304000$

$x = 16000$

Hence, the parts are 16000 and 8000

#Learn more :

Find total simple interest :

https://brainly.in/question/123276

Find rate of interest :

https://brainly.in/question/10561202