Question

4. एक गाडी विशिष्ट अंतर एकाच ठराविक वेगाने कापते. जर गाडीचा वेग 6 कि. मी
/तास वाढला असता तर ती तिच्या निर्धारित वेळेच्या 4 तास लवकर पोहचते. जर
गाडीचा वेग 6 किमी/तास कमी झाला असता तर गाडीला तिच्या निर्धारित वेळेपेक्षा 6 तास
जास्त लागतील. तर गाडीने एकूण किती किमी प्रवास केला?​

Answer 1

Step-by-step explanation:

A train travels a certain distance at the same speed. If the speed of the vehicle is 6 kph. I / Hr, she arrives 4 hours earlier than her scheduled time. If  the speed of the train was reduced to 6 km / hr, then the train would be 6 hours faster than its scheduled time  It will take more. So how many km did the train travel in total?  

• Consider time taken as t, speed as x and Distance as d.
• Time = Distance / Speed  
• So Speed = Distance / Time
•        x = d/t ----------1
• Now for the first case we have
•      d = (x + 6) (t – 4)
•      d = xt + 6t – 4x – 24
•     d = d – 4x + 6t – 24
•     6t – 4x = 24 ------------2
• Now for the second case we have
•     d = (x – 6) (t + 6)
•     d = xt + 6x – 6t – 36
•  d = d + 6x – 6t – 36
•     6x – 6t = 36 ----------------3
• Adding equation 2 and 3 we get
•     6t – 4x = 24
•    -6t + 6x = 36
•           2x = 60
•            x = 30
• Now substituting the value of x in eqn 2 we get
•   6t – 4(30) = 24
•   6t – 120 = 24
•   6t = 24 + 120
•   6t = 144
•     t = 144 / 6
•     t = 24 hours
• Now substituting the value of t and x in equation 1 we get
•     Distance d = x t
•                       = 30 x 24
•        Or d = 720 kms
• Therefore the train travelled a distance of 720 kms

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