4. Equal volumes of three monobasic acids of pH
3,4,5 are mixed in a vessel. The pH of the resultant
solution will be (log 3.7 = 0.57)
(1) 3.91
(2) 5.27
(3) 6.81
(4) 3.43
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Answer: pH of the resultant mixture will be 3.43
Explanation: Let the volume of each acid =V
pH of first, second and third acids =3,4 and 5 respectively
[H⁺]of first acid (M 1 )= 1×10⁻³
[H⁺]of second acid (M 2 )= 1×10⁻⁴
[H⁺]of third acid (M 3 )= 1×10⁻⁵
[H⁺] of the resultant mixture will be = 1×10⁻³ + 1×10⁻⁴ + 1×10⁻⁵ / 3 = 0.00037 = 3.7 x 10⁻⁴
Therefore pH of the resultant mixture will be - log [ 3.7 × 10⁻⁴] = 3.43
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