Question

4. Evaluate :
a
2b 2
(i)
+
20) - 2
- 4
2b
a
(ii) (4a + 3b)2 – (4a - 3b)2 + 48 ab.
5. If a + b = 7 and ab = 10; find a - b.
6. If a - b = 7 and ab = 18; find a + b.
u​

Answer 1

Step-by-step explanation:

Given that,

a+b=6………………………………..(1)

a-b=4…………………………………(2)

Adding equation (1) and (2),we get,

(a+b)+(a-b)=10

=> a+b+a-b=10

=> 2a=10

=> 2a/2=10/2

=> a=5

Putting a=5 in equation (1),we get,

5+b=6

=> b=6–5

=> b=1

Now,

a^2+b^2

=(5)^2+(1)^2

=25+1

=26

2nd Method:

a+b=6

On squaring both sides,

(a+b)^2=(6)^2

=> a^2+2ab+b^2=36…………………….(1)

a-b=4

On squaring both sides,

(a-b)^2=(4)^2

=a^2–2ab+b^2=16……………..………….(2)

Adding equation (1) and (2), we get,

(a^2+2ab+b^2)+(a^2–2ab+b^2)=36+16

=> a^2+2ab+b^2+a^2–2ab+b^2=52

=> a^2+a^2+b^2+b^2+2ab-2ab=52

=> 2a^2+2b^2=52

=> 2(a^2+b^2)=52

=> a^2+b^2=52/2

=>a^2+b^2=26

Hence, a^2+b^2=26 .