Question

4. Evaluate by using laws of exponents... only accurate answers... pls pls pls​

Answer 1

Answer:

1_2-3-+(45+45) 0986+"7; 086;!?

Answer 2

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4. (i)

$\displaystyle \Bigg(\frac{6 \times 10}{2^2 \times 5^3}\Bigg)^2\times \frac{25}{27} \\ \\ \\ = \Bigg(\frac{(3*2)* (2*5)}{2^2 * 5^3}\Bigg)^2 \times \frac{5^2}{3^3} \\ \\ \\= \Bigg(\frac{3*2*2*5}{2^2*5^3}\Bigg) \times \frac{5^2}{3^3} \\ \\ \\ = \Bigg(\frac{3*2^2*5}{2^2*5^3}\Bigg) \times \frac{5^2}{3^3} \\ \\ \\=\frac{3*2^2*5*5^2}{2^2*5^3*3^3} \\ \\ \\ =\frac{3*2^2*5^{1+2}}{2^2*5^3*3^3}\\ \\ \\= \frac{3*2^2*5^3}{2^2*5^3*3^3} \\ \\ \\ = 3^{1-3}*2^{2-2}*5^{3-3} \\ \\ \\ = 3^{-2} * 2^0*5^0$

$\displaystyle = \frac{1}{3^2} *1*1 \\ \\ \\ = \frac{1}{9}$

4. (ii)

$\displaystyle \frac{6^4 \times 9^2 \times 25^3}{3^2 \times 4^2 \times15^6} \\ \\ \\ = \frac{(2*3)^4*(3^2)^{2} * (5^2)^3}{3^2*(2^2)^2*(3*5)^6} \\ \\ \\ = \frac{2^4*3^4*3^4*5^6}{3^2*2^4*3^6*5^6} \\\\\\=\frac{2^4*3^{4+4}*5^6}{3^{2+6}*2^4*5^6}\\\\\\= \frac{2^4*3^8*5^6}{3^8*2^4*5^6}\\\\\\ = 2^{4-4}*3^{8-8}*5^{6-6}\\\\\\= 2^0*3^0*5^0\\\\\\=1*1*1\\\\\\= 1$

$\Large{\underline{\underline{\textsf{\maltese\: {\red{Additional Information :-}}}}}}$

• aᵐ × aⁿ = aᵐ ⁺ ⁿ

• aᵐ ÷ aⁿ = aᵐ ⁻ ⁿ

• a⁰ = 1

• $\sf(\dfrac{a}{b})^m = \dfrac{a^m}{b^m}$

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Express ( 3⁷× 3³ ) × 3³ as a exponential form.

See answer at :  https://brainly.in/question/32768487