Math, asked by ravinaravi619, 5 months ago

4. Examine if each of the following is a perfect square,
(1) 725 (i) 190 (ii) 841 (iv) 1089​

Answers

Answered by rupeshsingh79
2

Answer:

----->>>>Here is your answer<<<<--------

➠(x + 2)(27 - x) = 210➠(x+2)(27−x)=210

➠27x + 54 - {x}^{2} - 2x = 210➠27x+54−x

2

−2x=210

➠ - {x}^{2} + 25x - 156 = 0➠−x

2

+25x−156=0

➠ {x}^{2} - 25x + 156 = 0➠x

2

−25x+156=0

➠ {x}^{2} - 13x - 12x + 156 = 0➠x

2

−13x−12x+156=0

➠x(x - 13) - 12(x - 13) = 0➠x(x−13)−12(x−13)=0

➠(x - 13)(x - 12) = 0➠(x−13)(x−12)=0

➠x - 13 = 0➠x−13=0

➠x - 12 = 0➠x−12=0

➠x = 13➠x=13

➠x = 12➠x=12

HOPE IT HELPS YOU.

Answered by ravaanmaharajnavs189
1

Answer:

Step-by-step explanation:

A number is said to be perfect square is the factors of the number are in pair

We have given numbers

(i) 725 = 5×5×29

As the factors of 725 are not in pair so it is not a perfect square

(ii) 190 = 2×5×19

Factor of 190 are not in pair so it is not a perfect square

(iii) 841 = 29 ×29

Factor of 814 are in pair so 841 is a perfect square

(iv) 1089 = 3×3×11×11

As the factor of 1089 are in pair so it is a perfect square

Learn more

841 and 1089 a perfect square?

Examine:(With correct steps)

Using the prime factorization method find which of the following numbers are perfect squares 4225 second 1089 please answer me the solution

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