Question

4.Express the trigonometric ratios cssA, cscA, secA in terms of tanA​

Answer 1

tanA=

cotA

1

secA=

1+tan

2

A

=

1+

cot

2

A

1

sinA=

1−cos

2

A

=

1−

sec

2

A

1

=

1−

1+

cot

2

A

1

1

=

1−

1+cot

2

A

cot

2

A

sinA=

1+cot

2

A

1

Answer 2

Answer:

Step-by-step explanation:

Answer

tanA=  

cotA

1

​  

 

secA=  

1+tan  

2

A

​  

=  

1+  

cot  

2

A

1

​  

 

​  

 

sinA=  

1−cos  

2

A

​  

=  

1−  

sec  

2

A

1

​  

 

​  

=  

1−  

1+  

cot  

2

A

1

​  

 

1

​  

 

​  

=  

1−  

1+cot  

2

A

cot  

2

A

​  

 

​  

 

sinA=  

1+cot  

2

A

1

​  

 

​