Question

4. Exterior angle ∆ACD of a triangle is 100° and
∆ABC and ∆BAC are in the ratio of 2:3, find all the angles of the triangle​

Answer 1

1st angle=100°

Let the two other angles be 2x and 3x

According to question

2x+4x+100°= 180°

5x+100° =180°

5x = 180°-100°

x = 180/5

x=16°

So now

2x= 2× 16= 32°

3x = 3× 16=48°

Hence, the angles of a triangle are 100°, 48° and 32°