4. External dimensions of a wooden cuboidal box are 25 cm x 20 cm x 12 cm.
If the thickness of the wood is 2.8 cm all around, find the volume of the
wood contained in the box.
Answers
Answered by
20
Answer:
4212.096cm^3
Step-by-step explanation:
l=25,b=20,h=12
volume of external dimension=lbh
=25cm*20cm*12cm
l'=25-(2*2.8)=19.4,b'=20-(2*2.8)=14.4,h'=12-(2*2.8)=6.4
volume of internal dimension=l'b'h'
=19.4*14.4*6.4
volume of wood=volume of external dimension-volume of internal dimension
=lbh-l'b'h'
=25*20*12-19.4*14.4*6.4=4212.096cm^3
hence , required volume = 4212.096cm^3
Answered by
5
Answer:
External volume= 30*25*20 = 15000cm cube
internal dimensions= (30-4)cm*(25-4)cm*(20-4)cm
= 26cm*21cm*16cm
internal volume = 26cm*21cm*16cm
= 8736 cm cube
volume of wood = external volume - internal volume= (15000-8735)cm cube
=6265cm cube.
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