Math, asked by armaanjain840, 5 months ago

4. Factorise
8-4L-4m - 2Lm - 4n + 2Ln + 2mn - Lmn
(1) (2-L) (2 + m) (2 + n) ​

Answers

Answered by vanshikabansal1630
2

Answer:

you can find the answer from the picture attached

Attachments:
Answered by steffiaspinno
1

The factors are (2-L)(2-m)(2-n)

Step-by-step explanation:

The question can be solved by first grouping the terms( two terms) and then taking out whatever is common in the terms outside the bracket.

8-4L-4m + 2Lm - 4n + 2Ln + 2mn - Lmn

8-4L -4m + 2Lm - 4n + 2Ln + 2mn - Lmn

4(2-L)-2m(2-L)-2n(2-L)+mn(2-L)

(2-L) is common in all, so it can be taken out

(2-L)(4-2m-2n+mn)

(2-L)(2(2-m)-n(2-n))

(2-L)(2-n)(2-m)

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