Question

4. Factorize 5√5 x² + 30x + 8√√5 by splitting the middle term. 5. If the point (2k-3,k+2) lies on the graph of the equation 2x+3y+15=0,find the value of K.​

Answer 1

Step-by-step explanation:

$we \: are \: given \: the \: equation \\ 5 \sqrt{5} \: {x}^{2} + 30x + 8 \sqrt{5} = 0 \: \: \: (since \: we \: have \: to \: split \: middle \: term \: therefore \: the \: equation \: must \: be \: equal \: to \: 0) \\ 5 \sqrt{5} {x}^{2} + 20x + 10x + 8 \sqrt{5}= 0 \\ 5x( \sqrt{5}x + 4) + 2 \sqrt{5} ( \sqrt{5}x + 4) = 0 \\ (5x + 2 \sqrt{5} )( \sqrt{5}x + 4) = 0 \\ case \: 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: case \: 2 \\ 5x + 2 \sqrt{5} = 0 \: \: \: \: \: \: \: \: \: \: \: \: \sqrt{5}x + 4 = 0 \\ x = \frac{ - 2 \sqrt{5} }{5} \: \: \: \: \: \: \: \: \: \: \: \:x = \frac{ - 4}{ \sqrt{5} } \\ \\ sorry \: but \: i \: know \: only \: middle \: split \: not \: coordinates \: graph$

Answer 2

Answers :

4. (√5x + 2)(5x + 4√5) = √5(√5x + 2)(√5x + 4)

5. k = –15/7

Explanation :

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