Question

4. Factorize the following: y^3+y^2-y-1​

Answer 1

Step-by-step explanation:

The value of y3+y2−y−1 is

y3−y2+2y2−2y+y−1

=y2(y−1)+2y(y−1)+1(y−1)

=(y−1)(y2+2y+1)

=(y−1)[y2+y+y+1]

=(y−1)[y(y+1)+1(y+1)]

=(y−1)(y+1)2

Answer 2

Answer:

$y^3+y^2-y-1 \\ {y}^{2} (y + 1) - 1(y + 1) \\ = (y + 1)( {y}^{2} - 1) \\ = (y + 1)(y + 1)(y - 1)$