Question

4.
Fig. 12.15
A triangle and a parallelogram have the same base and the same area. If the side
the triangle are 26 cm. 28 cm and 30 cm, and the parallelogram stands on the
28 cm, find the height of the parallelogram.
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Answer 1

Answer:

12 cm

Step-by-step explanation:

the sides of the triangle=26 cm, 28 cm and 30 cm.

where A is the area of the triangle with sides a , b and c. and s be the semi perimeter

s = (a+b+c) / 2

s= (26+28+30)/2

s= 84/2 = 42

area of the triangle = √(42*(42-26)*(42-28)*(42-30)

= √(42*16*14*12)

=√(2*3*7*4*4*2*7*2*2*3)

= 2*4*3*2*7

= 336 cm^2

area of the parallelogram = area of the triangle

area of the parallelogram = base *height

therefore

28h = 336

where h is the height of the parallelogram

h= 336/28 =12cm