Question

4.Find a quadratic polynomial whose zeroes are 2 and -6

Respectively . Verify the relation between the

coefficients and zeroes of the polynomial.​

Answer 1

Answer:

THE FORMULA TO FIND QUADRATIC POLYNOMIAL IS

$k( {x}^{2} - ( \alpha + \beta )x + ( \alpha \beta ) \\ where \: the \: given \: first \: zero \: is \: \alpha \\ and \: the \: second \: zero \: is \: \beta$

Step-by-step explanation:

$k( {x}^{2} - ( \alpha + \beta )x + ( \alpha \beta ) \\ k( {x}^{2} - (2 - 6)x + {(2)( - 6)} \\ when \: there \: is \: no \: denomintors \\ \: in \: the \: given \: zeroes \: then \: the \: \\ k \: value \: becomes \: 1 \\ 1( {x}^{2} - ( - 4)x - 12) \\ {x}^{2} + 4x - 12$

HOPE IT WILL HELP YOU

PLZZ MARK AS BRAINLIST

Answer 2

AnsWer:-

↝α+β=2+(-6)

↝α+β=-4

↝αβ=2×-6

↝αβ=-12

✪Using the Formula

→k[x²-(α+β)x+αβ]

↝k[x²-(-4)x+(-12)]

↝k[x²+4x-12]

•Let k=1•

↝1[x²+4x-12]

☞x²+4x-12 is the Polynomial.

*Since The Zeros Form a Polynomial,It Verifies the Relation b/w coefficients and the zeros of the polynomial.*