Question

4. Find a quadratic polynomial whose zeroes are -9 and -1/9​

Answer 1

Answer:

p(x) = 9x² + 82x + 9

Explanation:

let n1 and n2 be the zeroes

we know that -b/a = n1 + n2

                              = -9 + (-1\9)

                              = -82/9

we also know that c/a = n1n2

                                       = -9*(-1/9)

                                       = 1

So, the initial polynomial will be

x² + 82/9 + 1

And on multiplying 9 to the polynomial in attempt to remove fractions, we get

9x² + 82 + 9

Have a good day!