Math, asked by harshita2964, 8 months ago

4. Find an angle which is:
(i) equal to its complement
(ii) equal to four times its supplement
(iii) equal to twice its supplement
(iv) equal to twice its complement
(v) equal to 4/5 of its Supplement.​

Answers

Answered by athithirajinikanth
3

Answer:

           *Complementary angles add up to 90 degrees,Thus the angle which is equal to its complement is 45 degree.

            *As you know some of the supplementary angles is 180. So lets take the first angle as x. So the value of 1st angle is 36 degree.

             * In this solution, the one supplement angle is taken by X and twice of supplement angle is 2X. So that it remains two supplement that is measured by angle at 180 degree and then consider it as X x+2x=180°, 3x=180°, x=180÷3=60°, 2×60=120°. Therefore, two supplement angles takes place by 180 degree.

               *if an angle is twice its complement you can represent the angle as x and other as 2x . since they are complement , there sum is 90 degrees . this means that one angle is 30 deg. the angle that is twice that value is 60 degrees.

                * Let angle be x. Therefore angle=80 degrees.

Answered by avikathapliyal28
3

Answer:

i) 45 degree is equal to its complement

ii) 144 degree

iii) 120 degree

iv) 60 degree

v) 80 degree

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