Question

4. find area of Triangle whose vertices is (5, 1), (3, 5) and (5.2).​

Answer 1

Area of a triangle with vertices (x1,y1) ; (x2,y2)  and (x3,y3)  is ∣∣∣∣∣2x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣∣∣∣∣

Hence, substituting the points (x1,y1)=(−5,−1) ; (x2,y2)=(3,−5)  and (x3,y3)=(5,2) in the area formula, we get

Area of triangle ABC  =∣∣∣∣∣2(−5)(−5−2)+(3)(2+1)+5(−1+5)

hope it will be useful

please follow me and mark mi as brainleast