Question

4. Find four solutions for each of the following equations:
(ii) 2 (x – 3) -3(y - 1) = 0​

Answer 1

Answer:

(y

Step-by-step explanation:

Let x = 0

2(0 - 3) - 3(y-1) = 0

2(-3) - 3y + 3 = 0

-6 - 3y + 3 = 0

-3y - 3 = 0

-3y = 3

y = 3/-3 = -1

(0, -1)

━━━━━━━━

If x = 2

2(2-3) - 3(y - 1) = 0

2(-1) - 3y +3 = 0

1 - 3y = 0

-3y = -1

y = -1/-3

y = 1/3

(2, 1/3)

━━━━━━━━

if x = 1

2(1-3) - 3(y-1) = 0

2(-2) - 3y + 3 = 0

-4 -3y + 3 = 0

-1 - 3y = 0

-3y = 1

y = 1/-3

y = -1/3

(1, -1/3)

━━━━━━━━

if x = -1

2(-1-3) - 3(y-1) =0

2(-4) - 3y + 3 =0

-8 + 3 - 3y = 0

-5 - 3y = 0

-3y = 5

y = 5/-3

y = -5/3

(-1, -5/3)

hence the 4 solutions for 2(x -3) - 3(y-1) = 0 are

(0, -1) , (2, 1/3) , (1, -1/3) , (-1, -5/3)

Answer 2

Step-by-step explanation:

hence the answer is 4 and is equal to 0......