4. Find out (A+B+C+D) such that AB ×CB =DDD.where
AB and CB are two-digit numbers and DDD is a three-
digit number.
(A) 21
(B) 19
(C) 17
(D) 18
Answers
Answer:
First concentrate on units. B(squared) should end with D. D≠B
Step-by-step explanation:
Why am I taking B as B squared? Because we are multiplying B by itself in AB X CB = DDD.
Possible values of D is 1,4,6 or 9
111=3∗37
444=2∗2∗3∗37
666=2∗3∗3∗37
999=3∗3∗3∗37=27∗37
Only one possibility is seen = 27∗37=999
In this answer, AB and CB are two digit numbers, and DDD is a three digit number.
Hope this helps :)
Answer:
Step-by-step explanation:
Primary SchoolMath 5+3 pts
4. Find out (A+B+C+D) such that AB ×CB =DDD.where
AB and CB are two-digit numbers and DDD is a three-
digit number.
(A) 21
(B) 19
(C) 17
(D) 18
Ask for details FollowReport by Nikshay2 5 hours ago
Answers
The Brain
Gangadharpatila123 · Ambitious
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haifamaryamaqeel
Haifamaryamaqeel Ambitious
Answer:
First concentrate on units. B(squared) should end with D. D≠B
Step-by-step explanation:
Why am I taking B as B squared? Because we are multiplying B by itself in AB X CB = DDD.
Possible values of D is 1,4,6 or 9
111=3∗37
444=2∗2∗3∗37
666=2∗3∗3∗37
999=3∗3∗3∗37=27∗37
Only one possibility is seen = 27∗37=999
In this answer, AB and CB are two digit numbers, and DDD is a three digit number.