Question

4. Find out the kinetic energy of a car of mass 3000 k moving with a constant
velocity of 60 km/hr.
[Ans. 416667) approximately)​

Answer 1

Explanation:

Kinetic energy=

Kinetic energy=(1 \div 2) \times m {v}^{2}(1÷2)×mv

Kinetic energy=(1 \div 2) \times m {v}^{2}(1÷2)×mv 2

Kinetic energy=(1 \div 2) \times m {v}^{2}(1÷2)×mv 2

Kinetic energy=(1 \div 2) \times m {v}^{2}(1÷2)×mv 2 Here,

Kinetic energy=(1 \div 2) \times m {v}^{2}(1÷2)×mv 2 Here,mass,m=3000kg

Kinetic energy=(1 \div 2) \times m {v}^{2}(1÷2)×mv 2 Here,mass,m=3000kgvelocity,v=60kmph=

Kinetic energy=(1 \div 2) \times m {v}^{2}(1÷2)×mv 2 Here,mass,m=3000kgvelocity,v=60kmph=60 \times 5 \div 18 = 16.67m \div s60×5÷18=16.67m÷s

Kinetic energy=(1 \div 2) \times m {v}^{2}(1÷2)×mv 2 Here,mass,m=3000kgvelocity,v=60kmph=60 \times 5 \div 18 = 16.67m \div s60×5÷18=16.67m÷sso Kinetic energy=3000×16.67=50010 joules

Answer 2

Explanation:

kinetic energy = mv^2/2

= 3000(3600)/2

= 1800 × 3000

= 5400000