Question

(4) Find p(0), p(1) and p(-1) in the following polynomials v) p(x) = 5x3 - x2 + 2x - 3 ​

Answer 1

The answer is in the image i attached.

Answer 2

We have:

[tex]p(x) = 5x^3 - x^2 + 2x - 3\\ p(0) = 5(0)^3 - (0)^2 + 2(0) - 3\\ = 5*0 - 0 + 2*0 -3\\ = -3\\ p(1) = 5(1)^3 - (1)^2 + 2(1) -3\\ = 5*1 - 1 + 2*1 -3\\ = 5 - 1 + 2 -3\\ = 3\\ p(-1) = 5(-1)^3 -(-1)^2 + 2(-1) -3\\ = 5*(-1) -(1) -2 -3\\ = -5 -1 -2 -3\\ = -11 [/tex]
So, p(0) = -3, p(1) = 3, p(-1) = -11

Hope this Helped!