Question

4. Find P(0), P(1) and P(2) for the polynomial
P(t) = 2 + t + 2t square - t cube​

Answer 1

Given

⇒p(t)=2+t+2t²-t³

To Find The value at

⇒p(0) , p(1) and (2)

Now take

⇒p(t)=2+t+2t²-t³

When P(0)

⇒P(0) = 2 + 0 + 2(0)t² - (0)³

⇒p(0) = 2

WhenP(1)

⇒P(1) = 2 + 1 + 2(1)²-(1)³

⇒P(1) = 3 + 2 - 1

⇒P(1) = 5 - 1

⇒P(1) = 4

When P(2)

⇒P(2) = 2 + 2 + 2(2)² - (2)³

⇒p(2) = 4 + 2×4 - 8

⇒P(2) = 4 + 8 - 8

⇒P(2) = 4

Answer

⇒P(0) = 2 , P(1) = 4 And P(2) = 4