Question

4. Find P (0), P(1), P(-1), P(2) for P(x)=x2+x-1.​

Answer 1

Answer:

For any equation p(some number) substitute that number instead of x to get ur solution

P(0) = -1,P(1) = 1, P(-1) = -1

Step-by-step explanation:

P(0)=(0)2 + (0) - 1

     =-1

P(1)=(1)2 + 1 - 1

    = 1

P(-1)=(-1)2 + (-1) - 1

     = 1 - 2

     = -1