Question

4) Find the 17th and 25th terms of an AP whose Ist term is 3 and common difference is 5​

Answer 1

Answer :-

• The 17ᵗʰ and 25ᵗʰ is 83 and 123 respectively.

Step-by-step explanation:

To Find:-

• The 17ᵗʰ and 25ᵗʰ

Solution:

Given that,

• The first term of A.P. = 3
• Common difference = 5

We know,

tₙ = a + ( n - 1 ) d,

Where,

• ₙ = nth term
• a = first term
• d = common difference.

According the question,

• The 17ᵗʰ term of A.P. is :-

⇒ tₙ = a + ( n - 1 ) d

⇒ t₁₇ = 3 + ( 17 - 1 ) 5

⇒ t₁₇ = 3 + ( 16 ) 5

⇒ t₁₇ = 3 + 16*5

⇒ t₁₇ = 3 + 80

⇒ t₁₇ = 83

• The 25ᵗʰ term of A.P. is :-

⇒ t₂₅ = 3 + ( 25 - 1 ) 5

⇒ t₂₅ = 3 + ( 24 ) 5

⇒ t₂₅ = 3 + 24*5

⇒ t₂₅ = 3 + 120

⇒ t₂₅ = 123

Hence,

• The 17ᵗʰ term of A.P. is 83.
• The 25ᵗʰ term of A.P. is 123.